x=(-(x/8)-12)^2

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Solution for x=(-(x/8)-12)^2 equation: 


x in (-oo:+oo)

x = (-(x/8)-12)^2 // - (-(x/8)-12)^2

x-(-(x/8)-12)^2 = 0

x-1*(-1/8*x-12)^2 = 0

x-1*(-1/8*x-12)^2 = 0

-1/64*x^2-2*x-144 = 0

-1/64*x^2-2*x-144 = 0

-1*(1/64*x^2+2*x+144) = 0

1/64*x^2+2*x+144 = 0

DELTA = 2^2-(1/64*4*144)

DELTA = -5

DELTA < 0

-1 = 0

-1 = 0

x belongs to the empty set

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